写在笔记之前

今天一个上午都在做第5个实验，一方面是上午的时间比较少，另一方面也是这个实验的代码量增大。现在来看，我的汇编能力已经有了一点，王爽这本书写的确实是很好，相信能为我的二进制研究打下基础。希望今天能再看完一章。

…

assume cs:code,ds:data,ss:stack

data segment
    dw 0123h,0456h,0789h,0abch,0defh,0fedh,0cbah,0987h
data ends

stack segment
    dw 0,0,0,0,0,0,0,0
stack ends

code segment
    start:
    mov ax,stack
    mov ss,ax
    mov sp,16
    mov ax,data
    mov ds,ax

    push ds:[0]
    push ds:[2]
    pop ds:[2]
    pop ds:[0]

    mov ax,4c00h
    int 21h
code ends

end start

---

assume cs:code,ds:data,ss:stack

data segment
    dw 0123h,0456h,0123h,0456h,0123h,0456h,0123h,0456h,0123h,0456h,0123h,0456h,0123h,0456h,0123h,0456h

stack segment
    dw 0,0
stack ends

code segment
    start:
    mov ax,stack
    mov ss,ax
    mov sp,16
    mov ax,data
    mov ds,ax

    push ds:[0]
    push ds:[2]
    pop ds:[2]
    pop ds:[0]

    mov ax,4c00h
    int 21h
code ends

end start

---

assume cs:code,ds:data,ss:stack

code segment
    start:
    mov ax,stack
    mov ss,ax
    mov sp,16
    mov ax,data
    mov ds,ax

    push ds:[0]
    push ds:[2]
    pop ds:[2]
    pop ds:[0]

    mov ax,4c00h
    int 21h
code ends

data segment
    dw 0123h,0456h
stack segment
    dw 0,0
stack ends

end start

---

assume cs:code

a segment
    db 1,2,3,4,5,6,7,8
a ends

b segment
    db 1,2,3,4,5,6,7,8
b ends

c segment
    db 0,0,0,0,0,0,0,0
c ends

code segment
    start:
    mov ax,cs
    sub ax,1
    mov ss,ax
    sub ax,1
    mov ds,ax
    sub ax,1
    mov es,ax

    mov cx,8
    mov bx,0
    s:mov ax,ds:[bx]
      add ax,es:[bx]
      mov ss:[bx],ax
      inc bx
    loop s

    mov ax,4c00h
    int 21h
code ends

end start

---

assume cs:code

a segment
    dw 1,2,3,4,5,6,7,8,9,0ah,0bh,0ch,0dh,0eh,0fh,0ffh
a ends

b segment
    dw 0,0,0,0,0,0,0,0
b ends

code segment
    start:
    mov ax,cs
    sub ax,1
    mov ss,ax
    mov sp,10h
    sub ax,2
    mov ds,ax
    mov cx,8
    mov bx,0
    s:push [bx]
      add bx,2
    loop s

    mov ax,4c00h
    int 21h
code ends

end start

…

今天看了将近三章，效率还算不错

第四章过的很快，没什么特别的。

编译链接的过程

再强化一次，masm.exe:编译源代码，产生目标文件（.obj）,link.exe:链接目标文件，产生可执行文件(.exe)。

…